What's the probability of drawing two kings in a row with a regular well shuffled deck of cards?|||There are 52 cards to start. Four of these 52 cards are kings. Therefore the probability of drawing a king on the first drawing [P(K1)] is 4/52 or 1/13.
After drawing one king there are only 51 cards remaining, of which three are kings. The probability of drawing a king on the second drawing [P(K2)] is 3/51.
The probability of drawing two kings in a row is therefore the product of both draws or
P(K1)*P(K2)
= 4/52 * 3/51
= 12/2652
which reduces to
= 1/221|||The probability of drawing one king x the probability of drawing a second king
1st king probability is 4/52 and probability of drawing a second king is then 3/ 52 so the probability is:
1/13 * 3/52 = 3/676 %26lt;--- ANSWER|||(4 kings/52 cards)*(3 kings/51 cards)=0.00452, 0.452 % chance
also 1/0.00452 becomes 221:1
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