Saturday, November 12, 2011

An earth satellite moves ina circular orbit at a speed of 7000 m/s. What is the orbital period?

An earth satellite moves ina circular orbit at a speed of 7000 m/s. What is the orbital period?|||= GM/v2


r: distance of the satellite from the center of Earth in m


M is the mass of Earth: 5.974 x 1024


v is the orbital speed: 7000 m/s





r = 6.674x 10-11 x 5.974 x 1024/70002


r = 8137445 meters from the center of the Earth


and : 8137445 鈥?6378100 = 1749345 meters from the surface of the Earth (Distance)





Calculate the orbital period.


Time = Distance/speed





distance : the circumference of the orbit,





2蟺 x 8137445 = 51129074 meters





Time = (51129074)/7000


Time = 7304 seconds





= 2.02 hours

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